A 970 kg car starts from rest on a horizontal roadway and accelerates eastward for 5 s when it reaches a speed of 25 m/s. What is the

Question

A 970 kg car starts from rest on a horizontal roadway and accelerates eastward
for 5 s when it reaches a speed of 25 m/s. What is the average force exerted on
the car during this time? (Hint: Find acceleration of the car, then use the equation
F=ma.)

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Tài Đức 4 years 2021-08-02T04:55:38+00:00 1 Answers 370 views 0

Answers ( )

  1. Verity
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    2021-08-02T04:57:12+00:00
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    Answer: 4850N

    Explanation:

    Mass of car = 970 kg

    Time = 5 s

    Speed = 25 m/s

    Average force exerted on the car = ?

    Recall that Force is the product of the mass of an object and the acceleration by which it moves

    i.e Force = mass x acceleration

    (Since, acceleration is the rate of change of velocity or speed per unit time)

    i.e Acceleration = Speed / Time

    Acc = 25m/s / 5s

    Acc = 5m/s^2

    Average force = mass x acceleration

    Avg force = 970 kg x 5m/s^2

    = 4850N

    Thus, the average force exerted on the car is 4850 Newton

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