A ray of light passes from air into a block of clear plastic. How does the angle of incidence in the air compare to the angle of refraction

Question

A ray of light passes from air into a block of clear plastic. How does the angle of incidence in the air compare to the angle of refraction in the plastic? A ray of light passes from air into a block of clear plastic. How does the angle of incidence in the air compare to the angle of refraction in the plastic? The angle of incidence is equal to the angle of refraction. The angle of incidence is greater than the angle of refraction. The angle of incidence is less than the angle of refraction. The two angles cannot be compared without additional information.

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Tài Đức 3 years 2021-07-31T23:29:33+00:00 1 Answers 60 views 1

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  1. Eirian
    0
    2021-07-31T23:30:48+00:00
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    Answer:

    The angle of incidence is greater than the angle of refraction

    Explanation:

    Refraction occurs when a light wave passes through the boundary between two mediums.

    When a ray of light is refracted, it changes speed and direction, according to Snell’s Law:

    n_1 sin \theta_1 = n_2 sin \theta_2

    where
    :

    n_1 is the index of refraction of the 1st medium

    n_2 is the index of refraction of the 2nd medium

    \theta_1 is the angle of incidence (the angle between the incident ray and the normal to the boundary)

    \theta_2 is the angle of refraction (the angle between the refracted ray and the normal to the boundary)

    In this problem, we have a ray of light passing from air into clear plastic. We have:

    n_1=1.00 (index of refraction of air)

    n_2=1.50 approx. (index of refraction in clear plastic)

    Snell’s Law can be rewritten as

    sin \theta_2 =\frac{n_1}{n_2}sin \theta_1

    And since n_2>n_1, we have

    \frac{n_1}{n_2}<1

    And so

    \theta_2<\theta_1

    Which means that

    The angle of incidence is greater than the angle of refraction

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