The acceleration of a baseball pitcher’s hand as he delivers a pitch is extreme. For a professional player, this acceleration phase lasts on

Question

The acceleration of a baseball pitcher’s hand as he delivers a pitch is extreme. For a professional player, this acceleration phase lasts only 50 ms, during which the ball’s speed increases from 0 to about 90 mph, or 40 m/s.
What is the force of the pitcher’s hand on the 0.145 kg ball during this acceleration phase? Express your answer with the appropriate units.

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Orla Orla 5 years 2021-07-30T07:44:11+00:00 1 Answers 235 views 0

Answers ( )

  1. hongcuc2
    0
    2021-07-30T07:45:49+00:00
    Reply

    Answer:

    116 N.

    Explanation:

    Given,

    mass of the ball, m = 0.145 Kg

    initial speed = 0 m/s

    Final speed = 40 m/s

    time = 50 ms = 0.05 s

    Force is equal to change in momentum per unit time

    F = \dfrac{m\Delta v}{\Delta t}

    F = \dfrac{0.145(40-0)}{0.05}

    F = 116 N

    Force of the pitcher hand on the ball is equal to 116 N.

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