Batman (mass = 88.6 kg) jumps straight down from a bridge into a boat (mass = 484 kg) in which a criminal is fleeing. The velocity of the bo

Question

Batman (mass = 88.6 kg) jumps straight down from a bridge into a boat (mass = 484 kg) in which a criminal is fleeing. The velocity of the boat is initially +8.25 m/s. What is the velocity of the boat after Batman lands in it?

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Helga 3 years 2021-07-29T09:33:53+00:00 1 Answers 256 views 0

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  1. thienthanh
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    2021-07-29T09:35:41+00:00
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    Answer:

    The velocity of the boat after Batman lands in it is 6.97 m/s.

    Explanation:

    Given that,

    Mass of batman, m = 88.6 kg

    Mass of boat, m’ = 484 kg

    The velocity of the boat is initially +8.25 m/s, v’ = 8.25 m/s

    We need to find the velocity of the boat after Batman lands in it. In this case, the conservation of linear momentum works. So,

    Initial momentum = final momentum

    mv+m'v'=(m+m')V

    v = 0 (as the batman was at rest initially)

    m'v'=(m+m')V\\\\V=\dfrac{m'v'}{(m+m')}\\\\V=\dfrac{484\times 8.25}{(88.6+484)}\\\\V=6.97\ m/s

    So, the velocity of the boat after Batman lands in it is 6.97 m/s.

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