block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s). What is the angular frequency ( ω ω ) o

Question

block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s). What is the angular frequency ( ω ω ) of oscillation? x ( t ) = 1.5 cos ( 20 t ) x(t)=1.5cos⁡(20t)

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Ben Gia 3 years 2021-07-28T14:05:42+00:00 1 Answers 24 views 0

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  1. Dau
    0
    2021-07-28T14:07:11+00:00
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    Answer:

    Angular frequency is 20 rad/s.      

    Explanation:

    Given that,

    A block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s) is given by :

    x(t)=1.5\cos(20\ t)…..(1)

    The general equation of oscillating particle is given by :

    x(t)=A\cos(\omega t)…….(2)

    Compare equation (1) and (2) we get :

    \omega=20\ rad/s

    So, the angular frequency of the oscillation is 20 rad/s.

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