A large aquarium of height 5 m is filled with fresh water to a depth of D = 2.20 m. One wall of the aquarium consists of thick plastic with

Question

A large aquarium of height 5 m is filled with fresh water to a depth of D = 2.20 m. One wall of the aquarium consists of thick plastic with horizontal length w = 8.20 m. By how much does the total force on that wall increase if the aquarium is next filled to a depth of D = 4.40 m? (Note: use g = 9.81 m/s2 and rho = 998 kg/m3.)

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Lệ Thu 5 years 2021-07-28T11:41:22+00:00 1 Answers 22 views 0

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  1. RobertKer
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    2021-07-28T11:42:59+00:00
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    Answer:

    P=21538.836\ Pa

    Explanation:

    Given:

    Initial depth of water in the aquarium,  D_i=2.2\ m

    width of a wall of aquarium, w=8.2\ m

    final depth of the water in the aquarium, D_f=4.4\ m

    Now the change in pressure on the wall:

    P=\rho.g.(D_f-D_i)

    P=998\times 9.81\times (4.4-2.2)

    P=21538.836\ Pa

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