10 points) A rubber ball and a lump of putty of the same mass m = 0.05 kg are thrown with the same speed v=10.0 m/s in positive x-direction

Question

10 points) A rubber ball and a lump of putty of the same mass m = 0.05 kg are thrown with the same speed v=10.0 m/s in positive x-direction against a vertical wall. The ball bounces back with the same speed v’=10.0 m/s in negative x-direction. The putty sticks to the wall. Which of the two objects (rubber ball and a lump of putty) experiences the greater momentum change?

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Latifah 4 years 2021-07-26T22:26:25+00:00 1 Answers 12 views 0

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  1. yenoanh
    0
    2021-07-26T22:27:52+00:00
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    Answer:

    the ball experiences the greater momentum change

    Explanation:

    You have to take into account that momentum change is given by

    \Delta p=mv_f-mv_b

    where vf and vb are the speed of the object after and before the impact.

    In the case of the ball you have

    \Delta p=(0.05kg)(-10.0\frac{m}{s})-(0.05kg)(10.0\frac{m}{s})=-1kg\frac{m}{s}

    where the minus of vf is included due to the motion is in an opposite direction regarding with vb

    And for the lump

    \Delta p=(0.05kg)(10.0\frac{m}{s})-(0.05kg)(0\frac{m}{s})=0.5kg\frac{m}{s}

    Hence, the ball experiences the greater change

    hope this helps!!

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