A tennis ball is struck in such a way that it leaves the racket with a speed of 31.0m/s in the horizontal direction. When the ball hits the

Question

A tennis ball is struck in such a way that it leaves the racket with a speed of 31.0m/s in the horizontal direction. When the ball hits the court, it is a distance of 13.3m from the racket. Find the height of the racket ball when it left the racket.

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Thanh Hà 5 years 2021-07-25T09:45:52+00:00 1 Answers 19 views 0

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  1. Doris
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    2021-07-25T09:47:11+00:00
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    Answer:

    Height of the racket ball = 0.86 m

    Explanation:

    Given:

    Speed of the tennis ball,v_x= 31 m/s

    Distance covered, R_x = 13.3 m

    We have to find the height of the racket ball when it left the racket.

    Lets say that the time taken by the ball to hit the court be ‘t’ seconds.

    ⇒ time=\frac{distance}{speed}

    ⇒ time=\frac{R_x}{v_x}

    ⇒ t=\frac{13.3\ m}{31.0\ ms^-^1}

    ⇒ t=0.42 seconds

    Now we have to find the height lets say that the height is ‘h’ meter.

    ⇒ h_y=u_yt + \frac{a_yt^2}{2}     …second equation of motion

    ⇒ h_y=0 + \frac{gt^2}{2}          …initial velocity = 0 and acceleration = gravity

    ⇒ h_y=\frac{9.8(0.42)^2}{2}

    ⇒ h_y=\frac{1.72}{2}

    ⇒ h_y=0.86 meter.

    So the height of the racket ball when it left the racket is of 0.86 m.

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