A heat release of 4800 J for 8 minutes is released in the conductor during the flow of electricity. What is the current in the conductor?

Question

A heat release of 4800 J for 8 minutes is released in the conductor during the flow of electricity. What is the current in the conductor? The conductor resistance is 1kΩ​

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niczorrrr 5 years 2021-07-24T08:57:30+00:00 1 Answers 20 views 0

Answers ( )

  1. Nho
    0
    2021-07-24T08:59:00+00:00
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    Answer: 0.1 Amps

    Explanation:

    Given that,

    heat released (H) = 4800 J

    Time taken (T) = 8 minutes

    Since the unit of time is seconds, convert 8 minutes to seconds

    (1 minute = 60 seconds

    8 minutes = 8 x 60 = 480 seconds)

    current in the conductor (I) = ?

    The conductor resistance (R) = 1kΩ​

    Convert kilo-Ohms (kΩ​) to ohms (Ω​)

    (If 1000Ω = 1kΩ

    1kΩ = 1000Ω)

    Now, apply the formula:

    H = I²RT

    4800J = I² x 1000Ω x 480 Seconds

    4800J = 480000Ω•I²

    Divide both sides by 480000Ω

    4800J/480000Ω = 480000Ω•I²/ 480000Ω

    0.01 = I²

    To get the value of I, find the square root of I²

    I = √0.01

    I = 0.1 Amps

    Thus, the current in the conductor is 0.1 Amps

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