Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation distance of 0.02

Question

Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation distance of 0.02 m. Determine the magnitude of the electrical force of repulsion between them

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MichaelMet 4 years 2021-07-22T10:31:13+00:00 1 Answers 47 views 0

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  1. thuthuy
    0
    2021-07-22T10:32:32+00:00
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    Answer:

    The electric force between them is 878.9 N

    Explanation:

    Given:

    Identical charge q = -6.25 \times 10^{-6}C

    Separation between two charges r = 0.02 m

    For finding the electrical force,

    According to the coulomb’s law

       F = \frac{k q^{2} }{r^{2} }

    Here, force between two balloons are repulsive because both charges are same.

    Where k = 9 \times 10^{9}

       F = \frac{9 \times 10^{9} \times (-6.25 \times 10^{-6} )^{2} }{4 \times 10^{-4} }

       F = 878.9 N

    Therefore, the electric force between them is 878.9 N

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