A potential difference of 53 mV is developed across the ends of a 12.0-cm-longwire as it moves through a 0.27 T uniform magnetic field at a

Question

A potential difference of 53 mV is developed across the ends of a 12.0-cm-longwire as it moves through a 0.27 T uniform magnetic field at a speed of 5.0 m/s. The magnetic field is perpendicular to the axis of the wire. What is the angle between the magnetic field and the wire’s velocity?

in progress 0
Thành Công 4 years 2021-07-21T17:54:35+00:00 1 Answers 68 views 0

Answers ( )

  1. Maris
    0
    2021-07-21T17:55:55+00:00
    Reply

    Answer:

    The angle between the magnetic field and the wire’s velocity is 19.08 degrees.                                            

    Explanation:

    Given that,

    Potential difference, V = 53 mV

    Length of the wire, l = 12 cm = 0.12 m

    Magnetic field, B = 0.27 T

    Speed of the wire, v = 5 m/s

    Due to its motion, an emf is induced in the wire. It is given by :

    \epsilon=Blv\sin\theta

    Here,

    \theta is the angle between magnetic field and the wire’s velocity

    \sin\theta=\dfrac{\epsilon}{Blv}\\\\\sin\theta=\dfrac{53\times 10^{-3}}{0.27\times 0.12\times 5}\\\\\sin\theta=0.327\\\\\theta=19.08^{\circ}

    So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )