The average intensity of light emerging from a polarizing sheet is 0.764 W/m^2, and the average intensity of the horizontally polarized ligh

Question

The average intensity of light emerging from a polarizing sheet is 0.764 W/m^2, and the average intensity of the horizontally polarized light incident on the sheet is 0.883 W/m^2. Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

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Helga 4 years 2021-07-21T04:05:21+00:00 1 Answers 214 views 0

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  1. thienthanh
    0
    2021-07-21T04:06:42+00:00
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    Answer:

    The angle that the transmission axis of the polarizing sheet makes with the horizontal is 21.55⁰

    Explanation:

    Given;

    average intensity of incident light, I = 0.764 W/m²

    average intensity of transmitted light, I₀ = 0.883 W/m²

    I = I₀Cos²θ

    where;

    θ is the angle that the transmission axis of the polarizing sheet makes with the horizontal.

    Cos²θ = I / I₀

    Cos²θ = 0.764/0.883

    Cos²θ = 0.8652

    Cosθ = √0.8652

    Cosθ = 0.9301

    θ = Cos⁻¹ 0.9301

    θ = 21.55⁰

    Therefore, the angle that the transmission axis of the polarizing sheet makes with the horizontal is 21.55⁰

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