A 500 kg satellite is placed in a circular orbit 7500 km above the surface of the earth. At this elevation, the acceleration of gravity is 4

Question

A 500 kg satellite is placed in a circular orbit 7500 km above the surface of the earth. At this elevation, the acceleration of gravity is 4.09 m/s2. Knowing that its orbital speed is 20,000 km/h, determine the kinetic energy of the satellite

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RI SƠ 5 years 2021-07-20T01:36:46+00:00 1 Answers 11 views 0

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  1. diemthu
    0
    2021-07-20T01:38:32+00:00
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    Answer:

    7.7 GJ

    Explanation:

    Kinetic wnergy is given by

    KE=½mv²

    Where KE denote kinetic energy, m is the mass of object and v is velocity. Normally, m is in Kg and v in m/s

    Conversion

    Given speed of satelite in km/h, we convert it into m/s by multiply by 1000/3600

    20000*1000/3600=5555.5555555555

    Rounded off, m=5555.56 m/s

    Substituting 500 kg for m and 5555.56 m/s for v then

    KE=½*500*5555.56²=7,716,061,728.4 rounded off as

    KE=7.7 GJ

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