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How much work does the electric field do in moving a proton from a point with a potential of +145 v to a point where it is -75 v ? express y
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Answer:
Explanation:
The work done by the electric field is given by:
W = qΔV
Since the positive charge moves from higher potential to lower potential, the work done in moving the proton is:
V = -q(V₂ – V₁)
W = -1.6 * 10⁻¹⁹ (-75 – 145)
W = 3.520*10³ * 10⁻²⁰ J
W = 3.520*10⁻¹⁷ J