In Case 1, a force F is pushing perpendicular on an object a distance L/2 from the rotation axis. In Case 2 the same force is pushing at an

Question

In Case 1, a force F is pushing perpendicular on an object a distance L/2 from the rotation axis. In Case 2 the same force is pushing at an angle of 30 degrees a distance L from the axis.1)In which case is the torque due to the force about the rotation axis biggest?
a. Case 1b. Case 2c. Same

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Yến Oanh 5 years 2021-07-18T06:51:50+00:00 1 Answers 36 views 0

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  1. ngochoa
    0
    2021-07-18T06:53:42+00:00
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    Explanation:

    Case 1,

    A force F is pushing perpendicular on an object a distance L/2 from the rotation axis. Torque is given by :

    \tau_1=Fd\sin \theta\\\\\tau_1=\dfrac{FL}{2}\sin (90)\\\\\tau_1=\dfrac{FL}{2}\ ..........(1)

    Case 2,

    The same force is pushing at an angle of 30 degrees a distance L from the axis. New torque is given by :

    \tau_2=Fd\sin \theta\\\\\tau_2=FL\sin (30)\\\\\tau_2=\dfrac{FL}{2}\ ..........(2)

    From equation (1) and (2), it is clear that the force in both cases is same.

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