A physicist’s right eye is presbyopic (i.e., farsighted). This eye can see clearly only beyond a distance of 97 cm, which makes it difficult

Question

A physicist’s right eye is presbyopic (i.e., farsighted). This eye can see clearly only beyond a distance of 97 cm, which makes it difficult for the physicist to read books and journals. Find the focal length and power of a lens that will correct this presbyopia for a reading distance of 25 cm, when worn 2 cm in front of the eye

in progress 0
Vodka 4 years 2021-08-02T20:34:39+00:00 1 Answers 17 views 0

Answers ( )

  1. Thunguyet
    0
    2021-08-02T20:35:43+00:00
    Reply

    Answer:

    f = 19,877 cm   and  P = 5D

    Explanation:

    This is a lens focal length exercise, which must be solved with the optical constructor equation

            1 / f = 1 / p + 1 / q

    where f is the focal length, p is the distance to the object and q is the distance to the image.

    In this case the object is placed p = 25 cm from the eye, to be able to see it clearly the image must be at q = 97 cm from the eye

    let’s calculate

            1 / f = 1/97 + 1/25

            1 / f = 0.05

            f = 19,877 cm

    the power of a lens is defined by the inverse of the focal length in meters

             P = 1 / f

             P = 1 / 19,877 10-2

             P = 5D

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )