Dentists’ chairs are examples of hydraulic-lift systems. If a chair weighs 1400 N and rests on a piston with a cross-sectional area of 1220

Question

Dentists’ chairs are examples of hydraulic-lift systems. If a chair weighs 1400 N and rests on a piston with a cross-sectional area of 1220 cm2, what force must be applied to the smaller piston with a cross-sectional area of 72 cm2 to lift the chair?

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Thu Cúc 4 years 2021-07-29T23:08:11+00:00 1 Answers 79 views 0

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  1. Edana
    0
    2021-07-29T23:10:02+00:00
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    Answer:

    Force applied to smaller cross section is

    = 82.63 N

    Explanation:

    As we know

    F_2 A_1 = F_1 A_2

    where F1, F2 signifies the weight of the two chair in a hydraulic-lift system

    And A_1, A_2 signifies the area of the two respective chairs in a hydraulic-lift system

    Given –

    F2=1400 N

    A1 =1220 Square centimeter

    A_2 = 72 Square centimeter

    Substituting the given values in above equation, we get –

    1400 * 72 = F1 * 1220\\F2 = 82.63

    Force applied to smaller cross section is

    = 82.63 N

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