A box is moved 20 m across a smooth floor by a force making a downward angle with the floor, so that there is effectively a 10 N force actin

Question

A box is moved 20 m across a smooth floor by a force making a downward angle with the floor, so that there is effectively a 10 N force acting parallel to the floor in the direction of motion and a 5 N force acting perpendicular to the floor the work done is:

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Khải Quang 4 years 2021-07-28T22:05:37+00:00 1 Answers 42 views 0

Answers ( )

  1. huyenthanh
    0
    2021-07-28T22:07:03+00:00
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    Answer:

    100 J

    Explanation:

    From the question, The work done by the forces in moving the box is given as

    W = FxdcosФ+Fydcosα………………. Equation 1

    Where W = Work done, Fx = force acting parallel to the floor, d = distance moved by the box, Ф = angle the parallel force makes with the floor, Fy = force acting perpendicular to the floor, α = angle the perpendicular force make with the floor.

    Give: Fx = 10 N, d = 20 m, Fy = 5 N, Ф = 0°, α = 90°

    Substitute into equation 1

    W = 10×10×cos0°+5×20×cos90°

    W = 10×10×1+0

    W = 100 J.

    Note: The work done by the perpendicular force is zero

    Hence the work done = 100 J

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