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An electron in the n = 6 level emits a photon with a wavelength of 410.2 nm. to what energy level does the electron move? <
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Answers ( )
Answer:
b. n = 2
Explanation:
To find the energy level you use the following formula from the Bohr’s model:
n2: initial state
n1: final state
To find the final state n2, is necessary to calculate the change in energy. This is made by using the following formula:
h: Planck’s constant = 6.62*10^⁻34Js
By replacing you obtain:
4.841*10^{-19}(6.242*10^{18}eV)=3.022eV (to use the formula (1) the unit of energy must be eV).
Finally, by doing n1 the subject of the formula (1) you obtain:
hence, the electron moves to the n=2 level
Answer:
It drops to energy level 2. Hence, answer is B
Explanation:
Using Rydberg’s formula to find the lower level.
The formula is:
1/w = R(1/L² – 1/U²), where w is the wavelength in meters, L is
the lower energy level ( which is what we want to find),
U is the upper level = 6
R is Rydberg’s constant =10,967,758 waves per meter for hydrogen.
Substituting values into the formula, we obtain: 1/(4.102 * 10**-7) = 10967759(1/L² – 1/36)
Change to decimal fractions for easier calculation and we get:
2437835 = 10967758(1/L² – 0.02777777) Divide both sides by 10967758 and
we obtain: 0.222273 = 1/L² – 0.02777777 Now add 0.0277777 to both sides
and obtain 0.250005 = 1/L²
Since 0.250005 is very close to ¼
Hence, we have
1/L² = ¼ so L² = 4 and L = 2.