Two point charges of +2.50 x 10^-5 C and -2.50 x 10^-5 C are separated by 0.50m. Which of the following describes the force between them?

Question

Two point charges of +2.50 x 10^-5 C and -2.50 x 10^-5 C are separated by 0.50m. Which of the following describes the force between them?

A): 90 N, repulsive
B): 90 N, attractive
C): 23 N, attractive
D): 45 N, attractive

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Thu Hương 3 years 2021-07-25T20:02:40+00:00 1 Answers 28 views 0

Answers ( )

  1. bonexptip
    0
    2021-07-25T20:04:05+00:00
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    Answer:

    Explanation:

    Q1 = +2.50 x 10^-5C and Q2 = -2.50 x 10^-5C, r = 0.50m, F=?

    Using Coulomb’s law:

    F = 1/(4πE) x Q1 x Q2/ r^2

    Where

    k= 1/(4πE) = 9 x 10^9Nm2/C2

    Therefore,

    F = 9x 10^9 x 2.50 x 10^-5 x2.50 x

    10^-5/. ( 0.5)^2

    F= 5.625/ 0.25

    F= 22.5N approximately

    F= 23N.

    To find the direction of the force: since Q1 is positive and Q2 is negative, the force along Q1 and Q2 is force of attraction.

    Hence To = 23N, attractive. C ans.

    Thanks.

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