What is the value of the equilibrium constant when the cell potential is found to be −0.29 v for a transfer of 2 moles of electrons at 298

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What is the value of the equilibrium constant when the cell potential is found to be −0.29 v for a transfer of 2 moles of electrons at 298.15 k?

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RuslanHeatt 5 years 2021-07-24T05:55:34+00:00 1 Answers 43 views 0

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  1. mit
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    2021-07-24T05:57:18+00:00
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    Answer:

    Explanation:

    The formula relating equilibrium constant and cell potential is given below

    E = RT / nF ln K , E is cell potential , T is temperature , n is no of moles , F is

    one farad .

    .29 = (8.31 x 298.15 / 2 x 96485)  ln K

    lnK = 22.58

    K = e ²²°⁵⁸

    = 6.4 x 10⁹

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )