Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of

Question

Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of radius 21 cm has a cord that has a pulling force of 50 N on it. What pulling force (in N) needs to be applied to the cord connecting the larger flywheel of radius 34 cm such that the combination does not rotate

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Philomena 5 years 2021-07-24T03:47:20+00:00 1 Answers 32 views 0

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  1. Latifah
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    2021-07-24T03:48:57+00:00
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    Answer:

    The pulling force applied to the cord connecting the larger flywheel is 30.88 N

    Explanation:

    Given;

    the radius of the smaller flywheel, r₁ = 21 cm

    force on the cord of the smaller flywheel, F₁ = 50 N

    the radius of the larger flywheel, r₂ = 34 cm

    The torque on each flywheel is equal, since there is no rotation.

    τ = Fr

    where;

    τ is torque on each flywheel

    F is the force on the cord of each flywheel

    r is the radius of each flywheel

    F₁r₁ = F₂r₂

    F_2 = \frac{F_1r_1}{r_2} \\\\F_2 = \frac{50*0.21}{0.34} \\\\F_2 = 30.88 \ N

    Therefore, the pulling force applied to the cord connecting the larger flywheel is 30.88 N

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