How many times louder is the intensity of sound at a rock concert in comparison with that of a whisper, if the two intensity lev

Question

How many times louder is the intensity of
sound at a rock concert in comparison with
that of a whisper, if the two intensity levels
are 130 dB and 2 dB, respectively?

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Thiên Ân 4 years 2021-07-19T14:15:20+00:00 1 Answers 14 views 0

Answers ( )

  1. yenoanh
    0
    2021-07-19T14:16:57+00:00
    Reply

    Answer:6.309\times 10^{12}

    Explanation:

    Given

    Intensity level of rock concert =130\dB

    Intensity level of Whisper =2\dB

    Intensity of sound is given by

    I=10\log _{10}(\frac{I}{I_o})

    where I_o=10^{-12}\ watts/m^2

    and difference in the intensity of the two sounds is db=130-2=128\ dB

    and

    db=10\log _{10} (\frac{I_1}{I_2})

    12.8=\log _{10}(\frac{I_1}{I_2})

    \frac{I_1}{I_2}=10^{12.8}

    \frac{I_1}{I_2}=6.309\times 10^{12}

    Thus intensity of Rock concert is  6.309\times 10^{12} times louder than that of a whisper

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )