ellus Three horizontal forces are pulling on a ring, at rest. F1 is 12.0 N at a 0° angle, and F2 is 18.0 N at a 90° direction

Question

ellus
Three horizontal forces are pulling on a
ring, at rest. F1 is 12.0 N at a 0° angle, and
F2 is 18.0 N at a 90° direction. What is the
x-component of F3?​

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Nguyệt Ánh 5 years 2021-09-03T23:03:44+00:00 1 Answers 51 views 0

Answers ( )

  1. ngockhue
    0
    2021-09-03T23:04:45+00:00
    Reply

    Answer:

    Explanation:

    Three forces are in equilibrium .

    Let us represent forces in vector form ie in the form of i and j .

    F₁ is acting along positive x axis ( at a 0° angle )

    F₁ = 12 i

    F₂ is acting along positive y axis ( at a 90° direction)

    F₂ = 18 j

    Suppose F₃ is represented by X i + Y j

    Total of three forces is zero .

    F₁ + F₂ + F₃ = 0

    12 i + 18 j + F₃ = 0

    F₃ = – 12i – 18 j

    So x – component of F₃ = – 12 i

    X – component of F₃ is equal to 12 N in magnitude and is acting in negative x direction ie at 180° direction .

    similarly y – component is 18 N acting in negative y direction.

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