A neutron star has about one and a half times the mass of our Sun but has collapsed to a radius of 10 kmkm . Part A What is the acceleration

Question

A neutron star has about one and a half times the mass of our Sun but has collapsed to a radius of 10 kmkm . Part A What is the acceleration due to gravity on the surface of this star in terms of the free-fall acceleration at Earth’s surface?

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Thu Thủy 5 years 2021-08-29T04:31:31+00:00 1 Answers 38 views 0

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  1. MichaelMet
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    2021-08-29T04:32:50+00:00
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    Answer:

    gₓ = 1.36 x 10¹³ g

    Explanation:

    The value of acceleration due to gravity at a certain place is given by the following formula:

    gₓ = GM/R²

    where,

    gₓ = acceleration due to gravity on the surface of neutron star

    G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

    M = Mass of the star = 10 * Mass of sun = (10)(2 x 10³⁰ kg) = 2 x 10³¹ kg

    R = 10 km = 10⁴ m

    Therefore,

    gₓ = (6.67 x 10⁻¹¹ N.m²/kg²)(2 x 10³¹)/(10⁴)²

    gₓ = 1.334 x 10¹⁴ m/s²

    Hence, comparing it with the free-fall acceleration at Earth’s Surface:

    gₓ/g = (1.334 x 10¹⁴)/9.8

    gₓ = 1.36 x 10¹³ g

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