A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 85 m horizontally away from an

Question

A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 85 m horizontally away from and below the point of release. What is the initial velocity of the ball in the horizontal direction? Express your answer in term of m/s. Write done the number only. Keep two significant figures.

in progress 0
Diễm Kiều 5 years 2021-08-27T19:17:29+00:00 1 Answers 286 views 0

Answers ( )

  1. minhkhue
    0
    2021-08-27T19:19:08+00:00
    Reply

    Answer: 18.81m/s^2

    Explanation:

    Given the following :

    Height of building = 0. 1 km = 100m

    Horizontal distance = 85m

    Using the equation :

    S = 1/2gt^2

    And S = 100, g = 9.8m/s^2

    100 = 0.5(9.8)(t^2)

    100 = 4.9(t^2)

    t^2 = (100 / 4.9)

    t^2 = 20.408

    t = 4.5175214

    t = 4.52s

    Therefore, initial velocity of ball in horizontal direction;

    Using the equation:

    S = ut + 0.5at^2

    a in horizontal direction = 0

    Therefore,

    S = ut

    85 = u × 4.52

    u = (85 / 4.52)

    u = 18.805

    u = 18.81m/s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )