A soccer player kicks a ball with an initial velocity of 10m/s at an angle of 30 degrees above the horizontal. Find the; a) magnitude of the

Question

A soccer player kicks a ball with an initial velocity of 10m/s at an angle of 30 degrees above the horizontal. Find the; a) magnitude of the horizontal component b) Vertical component c) The magnitude of the vector.

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Thái Dương 5 years 2021-08-27T10:48:33+00:00 1 Answers 10 views 0

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    2021-08-27T10:50:15+00:00

    Answer:

    a) V₀ₓ = 8.66 m/s

    b) V₀y = 5 m/s

    c) Magnitude of velocity vector = 10 m/s

    Explanation:

    a)

    The magnitude of the horizontal component of launch velocity can easily be given by the following formula:

    V₀ₓ = V₀ Cos θ

    where,

    V₀ₓ = horizontal component of velocity = ?

    V₀ = Launch Velocity = 10 m/s

    θ = Launch Angle of the ball with the horizontal = 30°

    Therefore,

    V₀ₓ = (10 m/s)(Cos 30°)

    V₀ₓ = 8.66 m/s

    b)

    The magnitude of the vertical component of launch velocity can easily be given by the following formula:

    V₀y = V₀ Sin θ

    where,

    V₀y = vertical component of velocity = ?

    V₀ = Launch Velocity = 10 m/s

    θ = Launch Angle of the ball with the horizontal = 30°

    Therefore,

    V₀y = (10 m/s)(Sin 30°)

    V₀y = 5 m/s

    c)

    The magnitude of the velocity vector will be equal to the resultant velocity or net velocity, which is 10 m/s.

    Magnitude of Velocity Vector = 10 m/s

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