12.0 V car battery has a voltage drop of 3.4 V when the starter draws 93 A of current. What is the resistance of the starter? O 88 m2 84 mg

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12.0 V car battery has a voltage drop of 3.4 V when the starter draws 93 A of current. What is the resistance of the starter? O 88 m2 84 mg O 80 m2

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Tài Đức 5 years 2021-08-26T19:50:59+00:00 1 Answers 11 views 0

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  1. Orla
    0
    2021-08-26T19:52:53+00:00
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    Answer:

    R_s = 0.093 \Omega

    Explanation:

    Voltage of the car battery = 12.0 V

    Voltage drop in the battery = 3.4 V

    The remainder of the voltage is the starter voltage, that is:

    Starter voltage = Initial battery voltage – voltage drop

    Starter voltage = 12.0 – 3.4

    Starter voltage, V_{s} = 8.6 V

    Current drawn by starter, I_s = 93 A

    According to Ohm’s law: V_s = I_s R_s

    Starter Resistance, R_s = V_s/I_s

    R_s = 8.6/93\\R_s = 0.093 \Omega

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