A 25N force is applied to a bar that can pivot around its end. The force is r=0.75 m away from the end of an angle at 0= 30. what is the tor

Question

A 25N force is applied to a bar that can pivot around its end. The force is r=0.75 m away from the end of an angle at 0= 30. what is the torque on the bar?

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RI SƠ 4 years 2021-08-25T10:37:23+00:00 1 Answers 10 views 0

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  1. Gerda
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    2021-08-25T10:38:29+00:00
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    Answer:

    9.375Nm

    Explanation:

    The formula for calculating torque τ = Frsin∅ where;

    F = applied force (in newton)

    r = radius (in metres)

    ∅ = angle that the force made with the bar.

    Given  F= 25N, r = 0.75m and ∅ = 30°

    torque on the bar τ  = 25*0.75*sin30°

    τ = 25*0.75*0.5

    τ = 9.375Nm

    The torque on the bar is 9.375Nm

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