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if san andreas fault slips 2.5 cm each year how far would it separate in 100 years
Question
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Answers ( )
Answer:
250cm or 2.5m
Explanation:
using direct variation
the length is = l
the time (year) = t
let k be the constant
so he have:
l=kt
2.5=k× 1
k= 2.5
Now in the next statement the 100 is given but not the length so
l=kt
~ l=k× 100 years
But k = 2.5
so :
l= 2.5×100
l= 250 cm
Hence it will be 250cm or 2.5m at which they will get separated