A man claims that he can hold onto a 16.0-kg child in a head-on collision as long as he has his seat belt on. Consider this man in a collisi

Question

A man claims that he can hold onto a 16.0-kg child in a head-on collision as long as he has his seat belt on. Consider this man in a collision in which he is in one of two identical cars each traveling toward the other at 59.0 mi/h relative to the ground. The car in which he rides is brought to rest in 0.05 s.
Find the magnitude of the average force needed to hold onto the child.
N

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Thu Cúc 4 years 2021-08-24T12:33:45+00:00 1 Answers 7 views 0

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  1. Amity
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    2021-08-24T12:35:32+00:00
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    Answer:

    F = -8440.12 N

    the magnitude of the average force needed to hold onto the child is 8440.12 N

    Explanation:

    Given;

    Mass of child m = 16 kg

    Speed of each car v = 59.0 mi/h = 26.37536 m/s

    Time t = 0.05s

    Applying the impulse momentum equation;

    Impulse = change in momentum

    Ft = ∆(mv)

    F = ∆(mv)/t

    F = m(∆v)/t

    Where;

    F = force

    t = time

    m = mass

    v = velocity

    Since the final speed of the car is zero(at rest) then;

    ∆v = 0 – v = -26.37536 m/s

    Substituting the given values;

    F = 16×-26.37536/0.05

    F = -8440.1152 N

    F = -8440.12 N

    the magnitude of the average force needed to hold onto the child is 8440.12 N

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