Bonnie and Clyde are sliding a 325 kg bank safe across the floor to their getaway car. The safe slides with a constant speed if Clyde pushes

Question

Bonnie and Clyde are sliding a 325 kg bank safe across the floor to their getaway car. The safe slides with a constant speed if Clyde pushes from behind with 377 N of force while Bonnie pulls forward on a rope with 353 N of force.

Required:
What is the safe’s coefficient of kinetic friction on the bank floor?

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Nguyệt Ánh 5 years 2021-08-22T23:53:35+00:00 1 Answers 17 views 0

Answers ( )

  1. thaiduong
    0
    2021-08-22T23:55:12+00:00
    Reply

    Answer:

    the safe’s coefficient of kinetic friction on the bank floor is \mathbf{\mu_k =0.2290}

    Explanation:

    GIven that:

    Bonnie and Clyde are sliding a 325 kg bank safe across the floor to their getaway car.

    So ,let assume they are sliding the  bank safe on an horizontal direction

    Clyde  →  Δ(bank safe)  → Bonnie

    Also; from the above representation; let not forget that the friction force F_{friction} is acting in the opposite direction ←

    where;

    F_{friction}  = \mu_k mg

    The safe slides with a constant speed

    If Clyde pushes from behind with 377 N of force while Bonnie pulls forward on a rope with 353 N of force.

    Thus; since the safe slides with a constant speed if the two conditions are met; then the net force acting on the slide will be equal to zero.

    SO;

    F_{net} = F_{Cylde} + F_{Bonnie} - F_{frition}

    F_{net} = F_{Cylde} + F_{Bonnie} - \mu_k \ mg

    Since the net force acting on the slide will be equal to zero.

    Then; F_{net} =0

    Also; let F_{Cylde} = F_c and F_{Bonnie} = F_B

    Then;

    0 = F_c + F_B - \mu_k \ mg

    \mu_k \ mg= F_c + F_B

    \mu_k = \dfrac{F_c + F_B}{\ mg}

    where;

    F_c = 377 \ N \\ \\ F_B = 353 \ N \\ \\ mass (m) = 325 \ kg

    Then;

    \mu_k = \dfrac{377 + 353}{325*9.81}

    \mu_k = \dfrac{730}{3188.25}

    \mathbf{\mu_k =0.2290}

    Thus; the safe’s coefficient of kinetic friction on the bank floor is \mathbf{\mu_k =0.2290}

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