“Suppose you tie a rock to the end of a 0.96 m long string and spin it in a horizontal circle with a constant angular velocity of 20.25 rad/

Question

“Suppose you tie a rock to the end of a 0.96 m long string and spin it in a horizontal circle with a constant angular velocity of 20.25 rad/s. If the tension in the string is 970 N, what is the mass of the rock (ignore gravity)

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Tryphena 3 years 2021-08-22T16:52:03+00:00 1 Answers 16 views 0

Answers ( )

  1. Helga
    0
    2021-08-22T16:53:42+00:00
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    Answer:

    The mass of the rock is  m = 2.46406 \ kg

    Explanation:

    From the question we are told that

       The length of the string is  l = 0.96 \ m

        The angular velocity is  w = 20.25 \ rad/s

         The tension on the string is T = 970 \ N

    Generally the centripetal force acting on the rock is mathematically evaluated as

           T = mlw^2

    making m the subject of the formula

          m = \frac{T}{w^2 * l}

    substituting values

         m = \frac{970}{(20.25^2) * (0.96)}

         m = 2.46406 \ kg

           

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