!! HELP PLEASE !! As seen from above, a 73.9 kg water skier is pulled by a 105 N force at a 22.5° angle, while the water creates a 74.8 N fo

Question

!! HELP PLEASE !! As seen from above, a 73.9 kg water skier is pulled by a 105 N force at a 22.5° angle, while the water creates a 74.8 N force pulling directly backward. What is the x-component of the total force on the skier?​

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Trung Dũng 3 years 2021-08-18T23:02:33+00:00 1 Answers 30 views 0

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  1. Jezebel
    0
    2021-08-18T23:04:16+00:00
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    Answer: The x-component of the total force 97N

    Explanation:

    Given the following :

    Mass (M) of skier = 73.9 kg

    Pull force on the skier = 105N

    Angle of pull = 22.5°

    The direct backward force directly pulling the skier = 74.8N

    the x-component of the total force on the skier

    The horizontal component of the force = Magnitude of the pulling force × cosine of the angle of pull (FCosΘ)

    FCosΘ = 105cos22.5°

    105cos22.5 = 105 × 0.9238795

    = 97.007350

    = 97N

    The backward force acting directly backward = 74.8N

    Therefore, net x – component of the total force equals ;

    97N – 74.8N = 22.2N

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