What is the force of gravity acting on a 1-kg m mass? (g = 9.8 m/s ^ 2)

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What is the force of gravity acting on a 1-kg m mass? (g = 9.8 m/s ^ 2)

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Edana Edana 5 years 2021-08-17T13:51:03+00:00 1 Answers 35 views 0

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  1. King
    0
    2021-08-17T13:52:56+00:00
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    Answer: Use this F=Ma.

    Explanation: So your answer will be

    F=1 Kg+9.8 ms-2

    So the answer will be

    F=9.8N

    How’d I do this?

    I just used Newton’s second law of motion.

    I’ll also put the derivation just in case.

    Applied force α (Not its alpha, proportionality symbol) change in momentum

    Δp α p final- p initial

    Δp α mv-mu (v=final velocity, u=initial velocity and p=v*m)

    or then

    F α m(v-u)/t

    So, as we know v=final velocity & u= initial velocity and v-u/t =a.

    So F α ma, we now remove the proportionality symbol so we’ll add a proportionality constant to make the RHS & LHS equal.

    So, F=kma (where k is the proportionality constant)

    k is 1 so you can ignore it.

    So, our equation becomes F=ma

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