if spiderman runs and jumps horizontally from the top of a 200m high building, what does he need his velocity to be to land on a building 10

Question

if spiderman runs and jumps horizontally from the top of a 200m high building, what does he need his velocity to be to land on a building 100m high, 10m away from him?

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Vân Khánh 3 years 2021-08-17T07:43:19+00:00 1 Answers 7 views 0

Answers ( )

  1. thugiang
    0
    2021-08-17T07:44:35+00:00
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    Answer:

    v = 2.22 m/s

    Explanation:

    First we apply the second equation of motion to the vertical motion of the body:

    s = Vi t + (1/2)gt²

    where,

    s = y = vertical distance covered = 200 m – 100 m = 100 m

    Vi = V₀y = Vertical Component of Initial Velocity = 0 m/s  (because spider man jumps horizontally, thus his velocity has no vertical component initially)

    t = Time Taken to Land on 100 m high building = ?

    g = 9.8 m/s²

    Therefore,

    100 m = (0 m/s)t + (0.5)(9.8 m/s²)t²

    t² = (100 m)/(4.9 m/s²)

    t = √(20.4 s²)

    t = 4.5 s

    Now, we analyze the horizontal motion. Neglecting air friction, the horizontal motion is uniform with uniform velocity. Therefore,

    s = vt

    where,

    s = x = horizontal distance covered = 10 m

    v = V₀ₓ = Horizontal Component of Initial Velocity = Initial Velocity = ?

    Therefore,

    10 m = v(4.5 s)

    v = 10 m/4.5 s

    v = 2.22 m/s

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