A 6.0-μF capacitor charged to 50 V and a 4.0-μF capacitor charged to 34 V are connected to each other, with the two positive plates connecte

Question

A 6.0-μF capacitor charged to 50 V and a 4.0-μF capacitor charged to 34 V are connected to each other, with the two positive plates connected and the two negative plates connected. What is the total energy stored in the 6.0-μF capacitor at equilibrium?

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Kim Cúc 4 years 2021-08-15T23:08:43+00:00 1 Answers 67 views 0

Answers ( )

  1. huyenthanh
    0
    2021-08-15T23:09:59+00:00
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    Answer:

    5702.88 J or 5.7mJ

    Explanation:

    Given that :

    C 1 = 6.0-μF

    C 2 = 4.0-μF

    V 1 = 50V

    V 2 = 34V

    Note that : Q = CV

    Q 1 = C1 * V1

    Q 1 = 50×6 = 300μC

    Q 2 = 34×4 = 136μC

    Parallel connection = C 1 + C 2

    = 6+4 = 10μC

    V = Qt/C

    Where Qt = Q1+Q2

    V = Q1+Q2/C

    V = 300+136/10

    V = 437/10

    V = 43.6volts

    Uc1 = 1/2×C1V^2

    = 1/2 × 6μF × 43.6^2

    = 1/2 × 6μF × 1900.96

    = 3μF × 1900.96volts

    = 5702.88J

    = 5702.88J/1000

    = 5.7mJ

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