Two 15-Ω and three 25-Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current that passes through each bulb?

Question

Two 15-Ω and three 25-Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current that passes through each bulb?

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Gerda 5 years 2021-08-14T22:08:31+00:00 1 Answers 37 views 0

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  1. Maris
    0
    2021-08-14T22:10:28+00:00
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    Answer:

    0.229A

    Explanation:

    Before we determine the amount of current in each bulb, we must first know that the same current flows in a series connected resistors. Since the Two 15-Ω and three 25-Ω light bulbs are connected in series, same current will flow in all of them.

    According to Ohm’s law, E = IRt where;

    E is the supply voltage = 24V

    I is the total current flowing in the circuit

    Rt is the total equivalent resistance.

    First, we need to calculate Rt.

    Rt = 15Ω+15Ω+25Ω+25Ω+25Ω (Two 15-Ω and three 25-Ω light bulb in series)

    Rt = 105Ω

    From ohms law formula, I = E/Rt

    I = 24/105

    I = 0.229Amp

    Since the total current in the circuit is 0.229A, therefore the amount of current that passes through each bulb is the same as the total current i.e  0.229A

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