A 0.500-V potential difference is maintained across a 1.50-m length of tungsten wire that has a cross-sectional area of 0.800 mm2. What is t

Question

A 0.500-V potential difference is maintained across a 1.50-m length of tungsten wire that has a cross-sectional area of 0.800 mm2. What is the current in the wire

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Hồng Cúc 4 years 2021-08-12T06:22:40+00:00 1 Answers 45 views 0

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  1. Delwyn
    0
    2021-08-12T06:24:03+00:00
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    Answer:

    5.95 A

    Explanation:

    From the question

    R = ρL/A………………… Equation 1

    Where R = resistance of the tungsten wire, ρ = Resistivity of the tungsten wire, L = length, A = cross sectional area.

    Given: L = 1.5 m, A = 0.8 mm² = 0.8×10⁻⁶ m, ρ = 5.60×10⁻⁸ Ω.m

    Substitute these values into equation 1

    R = 1.5(5.60×10⁻⁸)/0.8×10⁻⁶

    R = 0.084 Ω.

    Finally, using Ohm law,

    V = IR

    Where V = Voltage, I = current

    Make I the subject of the equation

    I = V/R…………… Equation 2

    I = 0.5/0.084

    I = 5.95 A

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