Suppose a 58-turn coil lies in the plane of the page in a uniform magnetic field that is directed into the page. The coil originally has an

Question

Suppose a 58-turn coil lies in the plane of the page in a uniform magnetic field that is directed into the page. The coil originally has an area of 0.150 m2. It is stretched to have no area in 0.100 s. What is the magnitude (in V) and direction (as seen from above) of the average induced emf if the uniform magnetic field has a strength of 1.10 T? magnitude V direction —Select— †\

in progress 0
RobertKer 5 years 2021-08-10T15:18:46+00:00 1 Answers 33 views 0

Answers ( )

  1. Latifah
    0
    2021-08-10T15:20:43+00:00
    Reply

    Answer:

    95.7v

    Explanation

    Using Faraday’s law of electromagnetic induction we know that rate of change in magnetic flux will induce EMF in closed loop

    So it is given as

    E= Ndစ/dt

    E= N BA-0/ deta t

    Given that

    N = 58turns

    B = 1.10T

    A = 0.150m^²

    Deta t= 0.1s

    now we have

    E = 58(1.10×0.150)/0.1

    = 95.7v

    Magnetic flux is decreasing, so the direction of the current will be to aid the decreasing flux $decrease= CLOCKWISE

    Explanation:

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )