6. You push an object, initially at rest, across a frictionless floor with a constant force for a time interval t, resulting in a final spe

Question

6. You push an object, initially at rest, across a frictionless floor with a constant force for a time interval t, resulting in a final speed of v for the object. You then repeat the experiment, but with a force that is twice as large. What time interval is now required to reach the same final speed v?

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Gia Bảo 5 years 2021-08-10T00:56:35+00:00 1 Answers 676 views 0

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  1. minhkhang
    0
    2021-08-10T00:57:39+00:00
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    Answer:

       t = t₀ / 2

    Explanation:

    In this exercise we must use Newton’s second law

              F = m a

              a = F / m

    now we can use kinematics

      as in object part of rest (v₀ = 0)

            v =a t₀

            t₀ = v / a

    these results are with the first experiment

    now repeat the experiment, but F = 2F₀

               a = 2F₀ / m = 2 a₀

              v = 2 a₀ t

              t = v / 2a₀

              t = t₀ / 2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )