An LR circuit consists of a 35-mH inductor, ac resistance of 12 ohms, an 18-V battery, and a switch. What is the current 5.0 ms after the sw

Question

An LR circuit consists of a 35-mH inductor, ac resistance of 12 ohms, an 18-V battery, and a switch. What is the current 5.0 ms after the switch is closed

in progress 0
Ben Gia 5 years 2021-08-09T21:46:45+00:00 1 Answers 32 views 0

Answers ( )

  1. hongcuc2
    0
    2021-08-09T21:48:11+00:00
    Reply

    Answer:

     I = 1.23 A

    Explanation:

    In an RL circuit current passing is described by

               I = E / R (1 – e^{-Rt/L})

    Let’s reduce the magnitudes to the SI system

            L = 35 mH = 35 10⁻³ H

            t = 5.0 ms = 5.0 10⁻³ s

    let’s calculate

             I = 18/12 (1 – e^{-12 .. 5 {10}^{-3}/35 .. {10}^{-3} }e (- 5 10-3 12/35 10-3))

             I = 1.5 (1- e^{-1.715})

             I = 1.23 A

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )