an electric device is plugged into a 110v wall socket. if the device consumes 500 w of power, what is the resistance of the device

Question

an electric device is plugged into a 110v wall socket. if the device consumes 500 w of power, what is the resistance of the device

in progress 0
Diễm Kiều 3 years 2021-08-09T15:08:07+00:00 1 Answers 6 views 0

Answers ( )

  1. Edana
    0
    2021-08-09T15:09:26+00:00
    Reply

    Answer: R=24.2Ω

    Explanation: Power is rate of work being done in an electric circuit. It relates to voltage, current and resistance through the following formulas:

    P=V.i

    P=R.i²

    P=\frac{V^{2}}{R}

    The resistance of the system is:

    P=\frac{V^{2}}{R}

    R=\frac{V^{2}}{P}

    R=\frac{110^{2}}{500}

    R = 24.2Ω

    For the device, resistance is 24.2Ω.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )