A body is thrown vertically upwards with a speed of 95m / s and after 7s it reaches its maximum height. How fast does it reach its maximum h

Question

A body is thrown vertically upwards with a speed of 95m / s and after 7s it reaches its maximum height. How fast does it reach its maximum height? What was the maximum height reached?

in progress 0
Kiệt Gia 4 years 2021-08-09T11:28:38+00:00 2 Answers 18 views 0

Answers ( )

  1. hongcuc2
    0
    2021-08-09T11:30:10+00:00
    Reply

    Explanation:

    u = 95 m/sec ( Initial speed)

    t = 7 sec ( Time of ascent)

    According to Equations of Motion :

    s = ut - \frac{1}{2} g {t}^{2}

    Max. Height = 95 * 7 – 4.9 * 49 = 424. 9 = 425 m

  2. Sapo1
    0
    2021-08-09T11:30:28+00:00
    Reply

    Answer:

    332.5 m

    Explanation:

    At the maximum height, the velocity is 0.

    Given:

    v₀ = 95 m/s

    v = 0 m/s

    t = 7 s

    Find: Δy

    Δy = ½ (v + v₀) t

    Δy = ½ (0 m/s + 95 m/s) (7 s)

    Δy = 332.5 m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )