A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wavelength of th

Question

A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wavelength of the constituent traveling waves is:

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Dulcie 4 years 2021-08-08T23:05:32+00:00 1 Answers 230 views 0

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    2021-08-08T23:07:24+00:00

    Answer:

    \lambda = 40 cm

    Explanation:

    given data

    string length = 30 cm

    solution

    we take here equation of length that is

    L = n \times \frac{1}{4} \lambda     ……………1

    so

    total length will be here

    L = \frac{\lambda}{2} +  \frac{\lambda}{4}\\

    L = \frac{3 \lambda }{4}

    so \lambda  will be

    \lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}

    \lambda = 40 cm

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