With what minimum speed must you toss a 130 g ball straight up to just touch the 14-m-high roof of the gymnasium if you release the ball 1.1

Question

With what minimum speed must you toss a 130 g ball straight up to just touch the 14-m-high roof of the gymnasium if you release the ball 1.1 m above the ground

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Nick 5 years 2021-08-07T09:20:15+00:00 1 Answers 255 views 0

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  1. thienan
    0
    2021-08-07T09:21:46+00:00
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    THIS IS THE COMPLETE QUESTION BELOW

    With what minimum speed must you toss a 130 g ball straight up to just touch the 14-m-high roof of the gymnasium if you release the ball 1.1 m above the ground

    And what speed does the ball hit the ground? Solve this problem using energy.

    Answer

    a)minimum speed must you toss a 130 g is 15.9090m/s

    b)speed the ball hit the ground is 16.57m/s

    Explanation:

    a)We know that For any closed/isolated system, the total energy is CONSERVED.

    K.E. lost by the ball=The change in P.E of the ball at 1.1m above the ground as well as the P.E. of the ball at 14 m-high roof

    This statement can be expressed as the expression below from K.E and P.E energy formula

    P.E. = mgh

    K.E. = (1/2)mv^2

    Therefore,

    (mgh1 – mgh2)=(1/2)mv^2

    Where h2=the ball height above the ground=1.1m

    h1=ball height at roof of the gymnasium= 14m

    Then if we substitute we have

    [(10) x (0.14) x (9.81)] – [(1.1) x (0.14) x (9.81)] = (1/2)(0.14)(v^2)

    16.45137=0.065V^2

    V=15.9090m/s

    minimum speed must you toss a 130 g is 15.9090m/s

    b)To calculate the speed the ball hit the ground?

    This is the highest point (14m-high roof),and the type of the energy the ball possesses is Po.tential energy only.

    At the lowest point (ground), the energy the ball possesses is K.E. only.

    P.E at 10m-high roof = K.E. at ground.

    (14) x (0.13) x (9.81) = (1/2) x (0.13) x v^2

    17.8542= 0.065V^2

    V= 16.57

    Therefore,And speed the ball hit the ground is 16.57m/s

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