the radius of the earth is 6380 km and the height of the mount everest is 8848m . if the value of the acceleration due to gravity on the top

Question

the radius of the earth is 6380 km and the height of the mount everest is 8848m . if the value of the acceleration due to gravity on the top of the mount everst is 9.77m/s²,calculate the value of acceleration due to gravity on the surface of the earth .what is the weight of a body of mass 50 kg on the top of mt.everest?

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Thiên Ân 5 years 2021-08-06T20:30:45+00:00 1 Answers 322 views 1

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  1. ngochoa
    0
    2021-08-06T20:32:31+00:00
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    Explanation:

    g = GM / R²

    9.77 m/s² = GM / (6.38×10⁶ m + 8848 m)²

    GM = 3.99×10¹⁴ m³/s²

    At the surface of the earth:

    g = GM / R²

    g = (3.99×10¹⁴ m³/s²) / (6.38×10⁶ m)²

    g = 9.80 m/s²

    At the top of Mount Everest, the weight of a 50 kg object is:

    F = mg

    F = (50 kg) (9.77 m/s²)

    F = 489 N

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