An electric heater supplies 5kw of power to atank of water assume all the energy supplied is converted into heat energy and the energy losse

Question

An electric heater supplies 5kw of power to atank of water assume all the energy supplied is converted into heat energy and the energy losses to the surrounding are negligible how long will it take to heat 500 kg of water in the tank from 25c to 100c specifiv heat capacity water 4200j/kgc​

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Bơ 5 years 2021-08-06T19:52:14+00:00 1 Answers 72 views 2

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  1. Giakhanh
    0
    2021-08-06T19:53:41+00:00
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    Answer:

    8hours 45minutes

    Explanation:

    Amount of heat energy used up by the electric substance = heat gained by the water.

    Amount of heat energy used up by the electric substance = Power * Time

    heat gained by the water. = mcΔt

    m is the mass of the water in kg

    c is the specific heat capacity

    Δt is the change in temperature

    Given parameters

    Power = 5kW = 5000W

    mass of water m = 500kg

    c = 4200J/kgC

    Δt = 100°C – 25°C = 75°C

    Required

    Time taken

    Substituting the given parameters into the formula

    Pt = mcΔt

    5000t = 500*4200*75

    5000t = 157,500,000

    Divide both sides by 5000

    t =  157,500,000/5000

    t = 31,500 secs

    t = (31,500/3600)hrs

    t = 8.75hours

    t = 8hours 45minutes

    Hence it takes 8hours 45minutes to heat 500 kg of water in the tank from 25c to 100c

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