Light of wavelength 500nm shines on a pair of slits. This produces an interference pattern on a screen 2.00m behind the slits. Measuring fro

Question

Light of wavelength 500nm shines on a pair of slits. This produces an interference pattern on a screen 2.00m behind the slits. Measuring from the center of the pattern, we find that the fifth dark spot is 4.00cm away. What is the spacing between the slits

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Kiệt Gia 5 years 2021-08-05T05:23:04+00:00 1 Answers 16 views 0

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  1. Sapo1
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    2021-08-05T05:24:20+00:00
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    Answer:

    The  value is  d = 0.000125 \ m

    Explanation:

    From the question we are told that

       The  wavelength is  \lambda = 500 \ nm = 500 *10^{-9 } \ m

        The  distance is of  the screen is  D = 2.0 \ m

        The  width of the fifth dark spot is y = 4.00 \ cm = 0.04 \ m

    Generally the width of a fringe is mathematically represented as

               y = \frac{ n * \lambda * D }{d }

    =>        0.04 = \frac{ 5 * 500 *10^{-9} * 2 }{d}

    =>        d = \frac{ 5 * 500 *10^{-9} * 2 }{0.04}

    =>        d = 0.000125 \ m

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