A kitten runs 24 x 10⁻² m away from its master in a straight line in 12.6 s, and then run halfway back in one-third the time. Calculate its

Question

A kitten runs 24 x 10⁻² m away from its master in a straight line in 12.6 s, and then run halfway back in one-third the time. Calculate its average velocity. ​

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Acacia 4 years 2021-08-02T20:36:38+00:00 1 Answers 8 views 0

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  1. mit
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    2021-08-02T20:38:23+00:00
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    Answer:

    1.43 × 10^-2 m/s

    Explanation:

    Given the following :

    Distance covered away from it’s master = D1 = 24×10^-2 m

    Time taken to cover the distance = t1 = 12.6s

    Then runs halfway back D2 =

    D1/ 2 = (24× 10^-2m) / 2 = 12 ×10^-2m

    Time taken =T2 = T1/3 = 12.6/3 = 4.2s

    Since the kitten ran in a straight line, the it is linear :

    Average speed

    Linear Average Velocity:

    Change in distance / change in time

    (D1 – D2) / (T2 – T1)

    (24 – 12)×10^-2 / (12.6 – 4.2)

    (12 × 10^-2)m / 8.4s

    1.4285 × 10^-2

    = 1.43 × 10^-2m/s

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